How To Perform Coordinates Affine Transformation Using Python?
Solution 1:
If it is just a translation and rotation, then this is a transformation known as an affine transformation.
It basically takes the form:
secondary_system = A * primary_system + b
where A
is a 3x3 matrix (since you're in 3D), and b
is a 3x1 translation.
This can equivalently be written
secondary_system_coords2 = A2 * primary_system2,
where
secondary_system_coords2
is the vector[secondary_system,1]
,primary_system2
is the vector[primary_system,1]
, andA2
is the 4x4 matrix:[ A b ][ 0,0,0,1 ]
(See the wiki page for more info).
So basically, you want to solve the equation:
y = A2 x
for A2
, where y
consist of points from secondary_system
with 1 stuck on the end, and x
is points from primary_system
with 1 stuck on the end, and A2
is a 4x4 matrix.
Now if x
was a square matrix we could solve it like:
A2 = y*x^(-1)
But x
is 4x1. However, you are lucky and have 4 sets of x
with 4 corresponding sets of y
, so you can construct an x
that is 4x4 like so:
x = [ primary_system1 | primary_system2 | primary_system3 | primary_system4 ]
where each of primary_systemi
is a 4x1 column vector. Same with y
.
Once you have A2
, to transform a point from system1 to system 2 you just do:
transformed = A2 * point_to_transform
You can set this up (e.g. in numpy
) like this:
import numpy as np
defsolve_affine( p1, p2, p3, p4, s1, s2, s3, s4 ):
x = np.transpose(np.matrix([p1,p2,p3,p4]))
y = np.transpose(np.matrix([s1,s2,s3,s4]))
# add ones on the bottom of x and y
x = np.vstack((x,[1,1,1,1]))
y = np.vstack((y,[1,1,1,1]))
# solve for A2
A2 = y * x.I
# return function that takes input x and transforms it# don't need to return the 4th row as it is returnlambda x: (A2*np.vstack((np.matrix(x).reshape(3,1),1)))[0:3,:]
Then use it like this:
transformFn = solve_affine( primary_system1, primary_system2,
primary_system3, primary_system4,
secondary_system1, secondary_system2,
secondary_system3, secondary_system4 )
# test: transform primary_system1 and we should get secondary_system1
np.matrix(secondary_system1).T - transformFn( primary_system1 )
# np.linalg.norm of above is 0.02555# transform another point (x,y,z).
transformed = transformFn((x,y,z))
Note: There is of course numerical error here, and this may not be the best way to solve for the transform (you might be able to do some sort of least squares thing).
Also, the error for converting primary_systemx
to secondary_systemx
is (for this example) of order 10^(-2).
You'll have to consider whether this is acceptable or not (it does seem large, but it might be acceptable when compared to your input points which are all of order 10^6).
Solution 2:
The mapping you are looking for seems to be affine transformation. Four 3D points not lying in one plain is the exact number of points needed to recover the affine transformation. The latter is, loosely speaking, multiplication by matrix and adding a vector
secondary_system = A * primary_system + t
The problem is now reduced to finding appropriate matrix A and vector t. I think, this code may help you (sorry for bad codestyle -- I'm mathematician, not programmer)
import numpy as np
# input data
ins = np.array([[3531820.440, 1174966.736, 5162268.086],
[3531746.800, 1175275.159, 5162241.325],
[3532510.182, 1174373.785, 5161954.920],
[3532495.968, 1175507.195, 5161685.049]]) # <- primary system
out = np.array([[6089665.610, 3591595.470, 148.810],
[6089633.900, 3591912.090, 143.120],
[6089088.170, 3590826.470, 166.350],
[6088672.490, 3591914.630, 147.440]]) # <- secondary system
p = np.array([3532412.323, 1175511.432, 5161677.111]) #<- transform this point# finding transformation
l = len(ins)
entry = lambda r,d: np.linalg.det(np.delete(np.vstack([r, ins.T, np.ones(l)]), d, axis=0))
M = np.array([[(-1)**i * entry(R, i) for R in out.T] for i inrange(l+1)])
A, t = np.hsplit(M[1:].T/(-M[0])[:,None], [l-1])
t = np.transpose(t)[0]
# output transformationprint("Affine transformation matrix:\n", A)
print("Affine transformation translation vector:\n", t)
# unittestsprint("TESTING:")
for p, P inzip(np.array(ins), np.array(out)):
image_p = np.dot(A, p) + t
result = "[OK]"if np.allclose(image_p, P) else"[ERROR]"print(p, " mapped to: ", image_p, " ; expected: ", P, result)
# calculate pointsprint("CALCULATION:")
P = np.dot(A, p) + t
print(p, " mapped to: ", P)
This code demonstrates how to recover affine transformation as matrix + vector and tests that initial points are mapped to where they should. You can test this code with Google colab, so you don't have to install anything.
Regarding theory behind this code: it is based on equation presented in "Beginner's guide to mapping simplexes affinely", matrix recovery is described in section "Recovery of canonical notation" and number of points needed to pinpoint the exact affine transformation is discussed in "How many points do we need?" section. The same authors published "Workbook on mapping simplexes affinely" that contains many practical examples of this kind.
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