Nested Dictionary With Duplicate Keys But Different Values

I'm having a hard time returning the values of each instance of $t in the nested dictionary below. What I need to do is pull each of the key-value pairs and add them individually

Solution 1:

Something like this?

>>>o = [ { "$t": "Chihuahua" }, { "$t": "Jack Russell Terrier" } ]>>>[ item["$t"] for item in o ]
['Chihuahua', 'Jack Russell Terrier']
>>>

Solution 2:

Is this what you are looking for? (It depends I think on how you want to handle the multiple values corresponding to the same $t.)

nestedDict = { "breed": [
                        {
                         "$t": "Chihuahua"
                         },
                         {
                          "$t": "Jack Russell Terrier"
                          }
                         ]
              }

dictEntries = [ (k, v) for dicList in nestedDict.values() for d in dicList for (k, v) in d.items() ]

flattenedDict = { }
for k, v in dictEntries:
    flattenedDict.setdefault( k, [] ).append( v )

print ( flattenedDict )

This gives you:

{'$t': ['Chihuahua', 'Jack Russell Terrier']}

Solution 3:

I don't understood what are you trying to do. If you want to create a Python dict from JSON ans get its values with the "$t" key, here it is (if not, comment and I delete the answer).

# Many thanks to Dogbert, whose answer I copied the list comprehension from # (changing a few things), and many thanks to slothrop, whose answer gave me # ideas for my variable name. Not for those people, I would have used a silly # name like `thing` and would have used a for loop.
import json

nested_dict = json.loads('{"breed": [{"$t": "Chihuahua"}, '
                                    '{"$t": "Jack Russell Terrier"}]}')
[dic["$t"] for dic in nested_dict["breed"]]

If you need the key-value pairs of every dict inside your dict:

key_and_value_pairs = []
for dic in nested_dict["breed"]:
    key_and_value_pairs.extend(dic.items())