How To Increment And Get The Next Ipv6 Network Address From The Current Network Address

Using standard python packages, how can I get the next few IPv6 network address if we give any IPv6 network address as input. Basically I want to iterate over the network address w

Solution 1:

The library ipcalc has routines to make math on ip addresses fairly easy. But if it would be preferable to not install ipcalc, a class that inherits from ipaddress.IPv6Network can be constructed.

Code

import ipaddress

classBetterIPv6Network(ipaddress.IPv6Network):

    def__add__(self, offset):
        """Add numeric offset to the IP."""
        new_base_addr = int(self.network_address) + offset
        return self.__class__((new_base_addr, self.prefixlen))

    defsize(self):
        """Return network size."""return1 << (self.max_prefixlen - self.prefixlen)

Test Code:

import itertools as it
network = BetterIPv6Network(u'4001:1::/32')
network_addrs = (network + i * network.size() for i in it.count())
print(next(network_addrs))
print(next(network_addrs))
print(next(network_addrs))

Results:

4001:1::/324001:2::/324001:3::/32

Python 3.4:

Python 3.4 did not accept tuples to init ipaddress.IPv6Network. This code will work around that.

import ipaddress

classBetterIPv6Network(ipaddress.IPv6Network):

    def__add__(self, offset):
        """Add numeric offset to the IP."""
        new_base_addr = int(self.network_address) + offset
        new_base_addr_str = str(self.__class__(new_base_addr)).split('/')[0]
        return self.__class__(
            new_base_addr_str + '/' + str(self).split('/')[1])

    defsize(self):
        """Return network size."""return1 << (self.max_prefixlen - self.prefixlen)