Python: Is There A Builtin That Works Similar But Opposite To .index()?

Just a forewarning: I just recently started programming and Python is my first language and only language so far. Is there a builtin that works in the opposite way of .index()? I'm

Solution 1:

As an answer to:

Is there a builtin I could use to input the position and return the item in the list?

You just need to access the list with it's index as:

>>> my_list = [1,2,4,8,16]
>>> my_list[4]
16# returns element at 4th index

And, this property is independent of language. All the languages supports this.

---

Based on your edit in the question, you may write your function as:

defcheck_value(my_list):
    # if len is less than 2iflen(my_list) < 2:
        if my_list and my_list[0] == 1:
            returnTrueelse:
            returnFalse 
    base_val = my_list[1] # as per the logic, it should be original number i.e num**1 for p, item inenumerate(my_list):
        if item != base_val ** p: 
            returnFalseelse:
        returnTrue

Sample run:

>>> check_value([1, 2, 4, 8])
True>>> check_value([1, 2, 4, 9])
False>>> check_value([1, 5, 25, 75])
False

Solution 2:

defpowers(n):
    for i in itertools.count(0):
        yield n**i


defis_powers(li):
   if li[0] == 1:
      iflen(li) > 1:
          returnall(x==y for x,y inzip(li,powers(li[1])))
      returnTruereturnFalse

is_powers([1, 2, 4, 8])
is_powers([1, 5, 25, 75])

maybe ... its really not clear what you are asking... this assumes that it always must start with a 1 if it is valid...